Good point, I think you're right, it would probably spike up in exactly m/c and then actually stay up for the entire second it takes for the circuit to close. One thing is giving me a headache: If you think of it as a series of capacitors, then the last one will conduct at 0,5s, but the current will not see our load until 1s after the switch is turned on, or just as the actual real world usable circuit would be completed. So that means our series of capacitors have been conducting for only half a second, but they have been creating a current at the load for a full second. What does that mean for what we would measure at the load for that first second?
Reply With Quote
