A question of probability

Fatguy - we know of only one Ace, which means we have three aces we can bink on the first draw, and two o nthe second.

3 aces out of 45 unknown cards: 3/45 on first draw
2 further aces out of 44 unknown: 2/44 on second draw

(3/45)*(2/44) = 0.3030% or about 330 to 1.

Course I rarely use anything but pokerstove to calculate shit like this anymore and maybe I've just gone full retard on how these calculations work. LOL.

FWIW whoever this happened to should quit their bitching, trying to figure out how unlikely it was they would be beat. Time better spent elsewhere.

That's one hell of a bad beat. The good thing is you win this the other 329 times so when it happens, just be happy you got it out of the way.

Yeah, so I just got home and ran this situation on poker stove - the odds I listed above are correct - about 330 to 1 (0.3030%)

Originally Posted by Penneywize

Fatguy - we know of only one Ace, which means we have three aces we can bink on the first draw, and two o nthe second.

3 aces out of 45 unknown cards: 3/45 on first draw
2 further aces out of 44 unknown: 2/44 on second draw

(3/45)*(2/44) = 0.3030% or about 330 to 1.

Course I rarely use anything but pokerstove to calculate shit like this anymore and maybe I've just gone full retard on how these calculations work. LOL.

FWIW whoever this happened to should quit their bitching, trying to figure out how unlikely it was they would be beat. Time better spent elsewhere.

^this

Text results appended to pokerstove.txt

8,910 games 0.005 secs 1,782,000 games/sec

Board: Qd 6h 5c
Dead:

equity win tie pots won pots tied
Hand 0: 00.303% 00.30% 00.00% 27 0.00 { AQo }
Hand 1: 99.697% 99.70% 00.00% 8883 0.00 { QQ }