|
|
 Originally Posted by Keith_MM
each block can be made up as
(
JxT TxJ (4/50*41/49*4/48)*2= 1312/117600
+
JTx TJx (4/50*4/49*40/48)*2= 1280/117600
+
xJT xTJ (42/50*4/49*4/48)*2= 1344/117600
)
*
This is wrong. If you think about it, you are saying that an AhJT flop happens more frequently than a JTAh flop.
In the first block you are working out the number of flops, given that the first card is a J and the third is a T. x can't be a 9 or a 6, so there are 42 possible cards for x. But we know the first card is one of the 4 jacks and the third card is one of the four Ts, so there are in fact only 40 possible cards for x. The same is true for the other blocks, since you have fixed the other two cards in each case.
In fact, you are double counting. In the JxT example you are including the T at position 3 in x, so counting it twice. This is why your xJT result > JxT > JTx.
|
Reply With Quote
