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				  Calculating how much FE needed for breakeven shove
			
			
					
					
			
				
					
						This has probably been done but I'm not the greatest math guy and I'm lazy. Had discussion with a friend about a hand in a live game that a third party played.  
 
 
Spare you the details but Hero has     on board of      turn   
BB (raised over limpers) bets $70 into pot of $125. Pot is $195, effective remaining stacks $405. 
 
Friend came up with this formula: 
0 = XP + (1 - X)(-LV + WH) 
 
Where... 
 
X = Breakeven Folding Frequency 
P = Current Size of the Pot 
L = Maximum Loss 
V = Villain's Equity 
W = Maximum Gain 
H = Hero's Equity 
 
So, we need to solve for X obv. 
 
0 = 195X + (1 - X) (-405 x 0.65 + 530 x 0.35) 
0 = 195X + -77.75(1 - X) 
0 = 195X + 77.75X - 77.75 
0 = 272.75X - 77.75 
X = 77.75/272.75 = 0.285 BE point for FE. (or 29%) 
 
 
So we need him to fold around 29% for a breakeven shove. Does this seem right? It jives with my half-ass way of figuring it out.
					 
				 
				
			 
			 
		  
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